Index: The Book of Statistical ProofsProbability DistributionsMultivariate continuous distributionsMultivariate normal distribution ▷ Linear transformation

Theorem: Let $X \in \mathbb{R}^n$ follow a multivariate normal distribution:

\[\label{eq:mvn} X \sim \mathcal{N}(\mu, \Sigma) \; .\]

Then, any linear transformation of $X$ is also multivariate normally distributed

\[\label{eq:mvn-lt} Y = AX + b \sim \mathcal{N}(A\mu + b, A \Sigma A^\mathrm{T})\]

where $A$ is an $m \times n$ matrix and $b$ is an $m$-dimensional vector.

Proof: The moment-generating function of a random vector $X$ is

\[\label{eq:vect-mgf} M_X(t) = \mathrm{E} \left( \exp \left[ t^\mathrm{T} X \right] \right)\]

and therefore the moment-generating function of the random vector $Y$ is given by

\[\label{eq:Y-mgf-s1} \begin{split} M_Y(t) &\overset{\eqref{eq:mvn-lt}}{=} \mathrm{E} \left( \exp \left[ t^\mathrm{T} (AX + b) \right] \right) \\ &= \mathrm{E} \left( \exp \left[ t^\mathrm{T} A X \right] \cdot \exp \left[ t^\mathrm{T} b \right] \right) \\ &= \exp \left[ t^\mathrm{T} b \right] \cdot \mathrm{E} \left( \exp \left[ t^\mathrm{T} A X \right] \right) \\ &\overset{\eqref{eq:vect-mgf}}{=} \exp \left[ t^\mathrm{T} b \right] \cdot M_X(A^\mathrm{T} t) \; . \end{split}\]

The moment-generating function of the multivariate normal distribution is

\[\label{eq:mvn-mgf} M_X(t) = \exp \left[ t^\mathrm{T} \mu + \frac{1}{2} t^\mathrm{T} \Sigma t \right]\]

and therefore the moment-generating function of the random vector $Y$ becomes

\[\label{eq:Y-mgf-s2} \begin{split} M_Y(t) &\overset{\eqref{eq:Y-mgf-s1}}{=} \exp \left[ t^\mathrm{T} b \right] \cdot M_X(A^\mathrm{T} t) \\ &\overset{\eqref{eq:mvn-mgf}}{=} \exp \left[ t^\mathrm{T} b \right] \cdot \exp \left[ t^\mathrm{T} A \mu + \frac{1}{2} t^\mathrm{T} A \Sigma A^\mathrm{T} t \right] \\ &= \exp \left[ t^\mathrm{T} \left( A \mu + b \right) + \frac{1}{2} t^\mathrm{T} A \Sigma A^\mathrm{T} t \right] \; . \end{split}\]

Because moment-generating function and probability density function of a random variable are equivalent, this demonstrates that $Y$ is following a multivariate normal distribution with mean $A \mu + b$ and covariance $A \Sigma A^\mathrm{T}$.

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Metadata: ID: P1 | shortcut: mvn-ltt | author: JoramSoch | date: 2019-08-27, 12:14.